程序读入20个整数，统计非负数个数，并计算非负数之和。
#include <stdio.h>
main( )
{ int i, a[20], s, count;
s=count=0;
for(i=0; ; i++)
scanf(“%d”, &a[i] );
for(i=0; i<20; i++)
{ if( a[i]<0 ) continue ;
;
count++;
}
printf(“s=%d\t count=%d\n”, s, count”);
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<20 s+=a[i]
i<20
s+=a[i]
i < 20
s += a[i]
s=s+a[i]
i<=20
else
s+=count
i＜20
i<20 s+=a[i]
i<20;
i<20 s=s+a[i]
i<20;if( a[i]>=0 )
i<20; s+=a[i]
s=s+s[i]
123
1
i<20;s+=a[i]
i < 20 s += a[i]
s = s+a[i]
1.i<20 2.s+=a[i]
i<20 s+=1
i<20 elsr
int arr[20]; int sum = 0; int count = 0; for (int i = 0; i < 20; ++i) { scanf("%d", &arr[i]); } for (int i = 0; i < 20; ++i) { if (arr[i] >= 0) { sum += arr[i]; count++; } } printf("非负数之和：%d\n", sum); printf("非负数个数：%d\n", count);
for(i=0; i<20 ; i++)
s+=a[i] ;
#include main( ) { int i, a[20], s, count; s=count=0; for(i=0; i<20; i++) scanf(“%d”, &a[i] ); for(i=0; i<20; i++) { if( a[i]<0 ) continue ; s+=a[i] ; count++; } printf(“s=%d\t count=%d\n”, s, count”); }
过
i<20 else
，
for(i=0;i<20; i++)
scanf('%d', &a[i] );
{
if (a[i]<0) continue;
s+=a[i];
printf('s=%d\t count=%d\n', s, count”);
题中的if判断写错了改为a[i]>=0 i < 20
s = s +a[i]
int main( ){
int i, a[20], s, count; s=count=0; for(i=0;i<20; i++) scanf("%d", &a[i]);
s=s+a[i]; count++;
printf("s=%d\t count=%d\n", s, count);
#include &l...
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