利用二分查...
题目解析及答案:
利用二分查找的关键在于数据一定要先有序,所以在查找前我们需要对数据进行排序。
#include<stdio.h>
#define N 10
void input(int num[], char name[N][8])
{
int i;
for (i = 0; i < N; i++)
{
printf("input NO.: ");
scanf("%d", &num[i]);
printf("input name: ");
getchar();
gets(name[i]);
}
}
void sort(int num[], char name[N][8])
{
int i, j, min, templ;
char temp2[8];
for (i = 0; i < N - 1; i++)
{
min = i;
for (j = i; j<N; j++)
if (num[min]>num[j]) min = j;
templ = num[i];
strcpy(temp2, name[i]);
num[i] = num[min];
strcpy(name[i], name[min]);
num[min] = templ;
strcpy(name[min], temp2);
}
printf("\n result:\n");
for (i = 0; i < N; i++)
printf("\n %5d%10s", num[i], name[i]);
}
void search(int n, int num[], char name[N][8])
{
int top, bott, mid, loca, sign;
top = 0;
bott = N - 1;
loca = 0;
sign = 1;
if ((n<num[0]) || (n>num[N - 1]))
loca = -1;
while ((sign == 1) && (top <= bott))
{
mid = (bott + top) / 2;
if (n == num[mid])
{
loca = mid;
printf("NO. %d , his name is %s.\n", n, name[loca]);
sign = -1;
}
else if (n < num[mid])
bott = mid - 1;
else
top = mid + 1;
}
if (sign == 1 || loca == -1)
printf("%d not been found.\n", n);
}
int main()
{
int num[N], number, flag = 1, c;
char name[N][8];
input(num, name);
sort(num, name);
while (flag == 1)
{
printf("\ninput number to look for:");
scanf("%d", &number);
search(number, num, name);
printf("continue ot not(Y/N)?");
getchar();
c = getchar();
if (c == 'N' || c == 'n')
flag = 0;
}
return 0;
}
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