一个循环队列Q的存储空间大小为M,其队头和队尾指针分别为front和rear，则循环队列中元素的个数为： 。
（rear-front+M）/M
(Q.rear-Q.front+M)%M
(Q.front-Q.rear+M)%M
(rear-front+M)%M
（r-f+m）%m
(rear-front+M)&M
(Q->rear - Q->front + M) % M
(rear - front + M) % M
（Q.rear-Q.front+M%M
（r-f+M)%M
(maxsize-(front-rear))%maxsize
rear+m-front）%m
(rear - front + M) %M
（rear-front+M）%M
(rear - front + M) % Maxsize
rear+M-front
(rear-front+m)%m
(r-f+m)%m
rear-front-1
（rear-front+m）%m
（rear+m-front）%m
(rear - front + m ) % m
v g f
(rear-front + m) % m
(rear-fronnt+M)%M
(front-rear-M)%M
（rear - front + M）% M
(Q.rear+M-Q.front)%M
(rear+m-front)%m
(rear-front +m)%m
((font+rear)-m)%m
M-1
答案：M-
(rear-front+m)％m
（rear-front+． m）% m
(rear - front +M)%M
(rear - front + M)%M
(rear-front+M)/%M
3
(Q.rear-Q.front+Maxsize)%Maxsize
(reae-front+MAXSIZE)%MAXSIZE
(rear-fornt+M)%M
(front-rear+M)%M
(rear－front+M)%M
（rear-front➕M）%M
size = (rear-front+m)%m；
r-f+m)%m
答案：(rear-front+M)...
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答案：(rear-front+M)%M
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