编程计算1＋3＋5+……＋101的值
#include <stdio.h>
void main()
{ int i, sum = 0;
for (i = 1; ; )
sum = sum + i;
printf("sum=%d\n", sum); }
i＜＝101，i＝i➕2
i<=101;i=i+2
i＜＝101，i＝i＋2
i<=101
i=i+2
i+=2
i <= 101 i += 2
i <= 101
i += 2
1
i
i<=101 i+2
i<=101 i+=2
i < 102
i<=101 i=i+2
i<101;1+2
i<102
i++
1.i<=101 2.i+=2
int main() {
int i,sum = 0; for(i = 1;i<=101;i=i+2){ sum = sum+i; } printf("sum = %d\n",sum); }
i≤10 i=2+i
1<=101 i+=2
i<102 i+=2
// 编程计算1＋3＋5+……＋101的值
for (i = 1; i<=101 ; i=i+2 )
#include void main() { int i, sum = 0; for (i = 1; i<=101 ; i=i+2; ) sum = sum + i; printf("sum=%d\n", sum); }
i<=101 i++
王泽茂 回复 王泽茂： 是i+2,没注意看题
Nature 回复 王泽茂： 应该是i+=2哦
i<=101;i++
i＜102 i+2
i <= 102 i +=2
i <= 101 i +=2
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i＜=101 i++
(i%2==1)&&i<=101
i <= 101 i+=2
i<= 99 i+=2
for (i = 1;i<102;i+=2)
#include <stdio.h> void main() { int i, sum = 0; for (i = 1; i <= 101 ; i += 2 ) sum = sum + i; printf("sum=%d\n", sum); }
i<=101;i+=2
i < =101
i = i+2
i<101,i++
for (i = 1; i<=101;i+=2)
printf("sum=%d\n", sum); return 0; }
for (i = 1; i<=101;i++)
#include <stdi...
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for (i = 1; i<=101 ; i=i+2; )
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