&x

a[i]==x

i<10

&x

a[i]==x

i<10

&x

a[i]==x

i<10

&x;a[i]=='\0';a[i]==x

#include void main() { int a[10], i, x; printf("input 10 integers:\n"); for (i = 0; i < 10; i++) { scanf("%d", &a[i]); } printf("input the number you want to find x: "); scanf("%d", &x); for (i = 0; i < 10; i++) { if (a[i] == x) { printf("the pos of x is: %d\n", i); break; } } if (i == 10) { // 如果循环结束后 i 仍然是 10，说明没有找到 x printf("can not find x!\n"); } }

&x

a[i] == x

i < 10

&x
a[i] == x

i < 10

x

a[i] == x

i < 10

&x

x==a[i]
i<10

&x

a[i] == x

i!=10

&x,a[i]!=x;a[i]=x

&x

x == a[i]

i == 10

&x

a[i] == x

i!=10

&x

a[i] == x

i<10

&x

a[i]==x

i<10

&x a[i]==x i<10

1.&x 2. 3.x==a[i]

&x

a[i] == x

i != 10

1

&x
a[i]==x
i<10

&x

a[i]==x

i<10

&x a［i］==x i<10

X

a[i]==x

i<=9

&x

a[i]==x

i<10

&x

a[i]==x

i<10

&x a[i]==x a[i]==x

&x

a[i]==x

x<10

下面程序的功能是在a数组中查找与x值相同的元素所在位置,请填空。

#include <stdio.h>

void  main()

{ int a[10],i,x;

printf(“input 10 integers：”);

for(i=0;i<10;i++)

scanf(“%d”,&a[i]);

printf(“input the number you want to find x：”);　

scanf(“%d”,   &x   );

for(i=0;i<10;i++)

if(    )

break;

if(  a[i]==x     )

printf(“the pos of x is：%d\n”,i);

else printf(“can not find x！\n”);

}

x

a[i]==x

i<10

x

a[i]==x

i<10

&x

x==a[i]

i<10

&x

a[i]==x

i<10

#include void main() { int a[10],i,x; printf(“input 10 integers：”); for(i=0;i<10;i++) scanf(“%d”,&a[i]); printf(“input the number you want to find x：”);　 scanf(“%d”, &x ); for(i=0;i<10;i++) if( x==a[i] ) break; if( i<10 ) printf(“the pos of x is：%d\n”,i); else printf(“can not find x！\n”); }

&x

a[i]==x

a[i]!=x

&X

a[i]==X

&x a[i]==x i<10

&x

a[i]==x

i<10

&x

a[i]==x

a[i]==x

&x

a[i]==x

i<10

&x

a[i]==x

i<10

&x

a[i]==x

i<10

&x x ==a[i] i < 10

&x

x==a[i]

i<10

&x

x==a[i]

i<10

&x i=9 a[i]==key

，

&x a[i]==x i>=0&&i<10

&x x==a［i］ i＜10

&x x==a［i］ i＜10

&x

a[i] == x

i < 10

&x     a[i] == x    i < 10

#include <stdio.h>

void  main()

{ int a[10],i,x;

printf('input 10 integers：');

for(i=0;i<10;i++)

scanf('%d',&a[i]);

printf('input the number you want to find x：');　

scanf('%d',&x);

for(i=0;i<10;i++)

if(a[i]==x)

break;

if(i<10)

printf('the pos of x is：%d\n',i);

else printf('can not find x！\n');

}

&x

a[i]=='x'

i<10

#include <stdio.h>

void  main()

{ int a[10],i,x;

printf(“input 10 integers：”);

for(i=0;i<10;i++)

scanf(“%d”,&a[i]);

printf(“input the number you want to find x：”);　

scanf(“%d”,   &x   );

for(i=0;i<10;i++)

if(   a[i]==x  )

break;

if(   i<10    )

printf(“the pos of x is：%d\n”,i);

else printf(“can not find x！\n”);

}

&x

a[i]==x

i==10

&x

a[i] == x

i < 10

&x

a[i] == x

i < 10

&x

a[i] == x

i < 10

&x

a[i]==x

i<10

&x

a[i]==x

i<10

&x

a[i]==x

i<10

&x

X ==a[i]

i < 10

&x

a[i]==x

i<10

&x

a[i]==x

i<10

#include <stdio.h>

        void  main()

         { int a[10],i,x;

           printf(“input 10 integers：”);

     for(i=0;i<10;i++)

scanf(“%d”,&a[i]);

           printf(“input the number you want to find x：”);　

scanf(“%d”,  &x    );

           for(i=0;i<10;i++)

if(  x==a[i]   )

break;

           if(   i<10    )

printf(“the pos of x is：%d\n”,i);

           else printf(“can not find x！\n”);

        }

&x

a[i] == x

x < 10

&x

!(x>=0&&x<=9)

a[i]==x

&x

x==a[i]

i<10

%x

a[i]==x

i!=10

&x

x==a[i]

i<10

&x 

x==a[i]

i<10

&x x==a[i] i<10

x

服了这个排版

&x, a[i] == x ,i < 10

&x a[i]==x x

1. &x
2. a[i]==x
3. a[i]==x

&x

a[i]==x

i < 10

后2空 自己错了 第2空 与break搭错了

1.&x

2.a[i]==x

3.i<10

&x

a[i]==x

i<10

&x

a[i]==x

i!=11

&x

a[i]==x

i<10

参考答案 #include void main() { int a[10],i,x; printf(“input 10 integers：”); for(i=0;i<10;i++) scanf(“%d”,&a[i]); printf(“input the number you want to find x：”);　 scanf(“%d”, &x ); for(i=0;i<10;i++) if( x==a[i] ) break; if( i<10 ) printf(“the pos of x is：%d\n”,i); else printf(“can not find x！\n”); }

&x

a[i]==x

i<10

&x

a[i]==x

i<10

&x

x==a[i]

i<10

&x

x==a[i]

i<10

下面程序的功能是在a数组中查找与x值相同的元素所在位置,请填空。

#include <stdio.h>

 void  main()

 { int a[10],i,x;

    printf(“input 10 integers：”);

    for(i=0;i<10;i++)

                 scanf(“%d”,&a[i]);

    printf(“input the number you want to find x：”);　

    scanf(“%d”, &x);

    for(i=0;i<10;i++)

           if((a[i] == x )

                break;

           if( i < 10)

                 printf(“the pos of x is：%d\n”,i);

           else printf(“can not find x！\n”);

        }

&x

a[i] == x

i < 10

&x

x==a[i]

i<10

&x

a[i]==x

i<10

&x

x==a[i]

i<10

&x

x != a[9]

x=a[i]

&x

x==a[i]

i<10

&x

a[i]==x

i<10

&x

a[i]==x

i<10

&x;

a[i]==x;

i<10;

&x

a[i]==x

i<10

&x

a[i]==x

i<10