int main()
{
int day,month,year,sum;
printf("Pleas input year,month,day\n");
scanf("%d%d%d",&year,&month,&day);
switch(month)
{
case 1:sum=0;break;
case 2:sum=31;break;
case 3:sum=59;break;
case 4:sum=90;break;
case 5:sum=120;break;
case 6:sum=151;break;
case 7:sum=181;break;
case 8:sum=212;break;
case 9:sum=243;break;
case 10:sum=273;break;
case 11:sum=304;break;
case 12:sum=334;break;
default:break;
}
sum=sum+day;
if(month>2&&(year%400==0||year%4==0&&year%100!=0))
++sum;
printf("It is the %dth day.",sum);
return 0;
}
登录后提交答案