#include<stdio.h>
#include<math.h>
int main()
{
    int num, num1, num2, a[50] = {0};
    int  i = 0;
    printf("输入一个十进制数：");
    scanf("%d", &num);
    while (num != 0) {
        num1 = num;
        num2 = num % 2;
        num /= 2;
        a[i] = num2;
        i++;
        printf("step%d:%d/2,余数=%d，商=%d\n",i, num1, num2, num);
    }
    printf("十进制%d转换为二进制位",num1);
    for(int j=i-1;j>= 0; j--) 
        printf("%d", a[j]);
    return 0;
}

#include #include long long convertDecimalToBinary(int n); int main() { int n; printf("输入一个十进制数: "); scanf("%d", &n); printf("十进制数 %d 转换为二进制位 %lld", n, convertDecimalToBinary(n)); return 0; } long long convertDecimalToBinary(int n) { long long binaryNumber = 0; int remainder, i = 1, step = 1; while (n!=0) { remainder = n%2; printf("Step %d: %d/2, 余数 = %d, 商 = %d\n", step++, n, remainder, n/2); n /= 2; binaryNumber += remainder*i; i *= 10; } return binaryNumber; }

#include <stdio.h>
#include<stdlib.h>
#include<string.h>
#include<math.h>
int main(void)
{
    int n[50],t=-1,sum=0;
    int num,num1;

    puts("请输入一个十进制数");
    scanf("%d", &num);
    num1 = num;
  do{ 
        t++;
        n[t] = num % 2;  
        printf("Step %d %d/2,余数=%d,商=%d: \n", t+1,num,n[t],num/2);
         num /= 2;
  } while (num> 0);//商大于0
  printf("%d的二进制为：\n", num1);
    for (int i = t; i >= 0; i--) {//--
        printf("%d", n[i]);
    }
    return 0;
}