C++

逐个单独处理年末和月末的情况 

#include <iostream>
#include <iomanip>
using namespace std;
bool isLeapYear(int year){
	return (year % 4 == 0 && (year % 100 != 0 || year % 400 == 0));
}
void show(int year, int month, int day){
	if(month == 12 && day == 31){
		year += 1;
		month = 1;
		day = 1;
	}
	else if((month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10) && day == 31){
		month += 1;
		day = 1;
	}
	else if((month == 4 || month == 6 || month == 9 || month == 11) && day == 30){
		month += 1;
		day = 1;
	}
	else if(month == 2 && day == 29 && isLeapYear(year)){
		month += 1;
		day = 1;
	}
	else if(month == 2 && day == 28 && !isLeapYear(year)){
		month += 1;
		day = 1;
	}
	else{
		day += 1;
	}
	cout << setw(4) << setfill('0') << year << "-" << setw(2) << setfill('0') << month << "-" << setw(2) &l...