C++

果然是同一所大学的题，和1437差不多。不过就是加1天改为了加past天

原题：1437 - 日期类 _N诺计算机考研 (noobdream.com)

我的1437做法：日期类 题解：_P1437_N诺计算机考研 (noobdream.com)

#include <iostream>
#include <iomanip>
using namespace std;
bool isLeapYear(int year){
	return (year % 4 == 0 && (year % 100 != 0 || year % 400 == 0));
}
void show(int year, int month, int day, int past){
	for(int i = 0; i < past; i++){
		if(month == 12 && day == 31){
			year += 1;
			month = 1;
			day = 1;
		}
		else if((month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10) && day == 31){
			month += 1;
			day = 1;
		}
		else if((month == 4 || month == 6 || month == 9 || month == 11) && day == 30){
			month += 1;
			day = 1;
		}
		else if(month == 2 && day == 29 && isLeapYear(year)){
			month += 1;
			day = 1;
		}
		else if(month == 2 && day == 28 && !isLeapYear(year)){
			month += 1;
			day = 1;
		}...