统计字符 题解:需要考虑l2中没有的情况
while(1):
try:
n1=list(input())
# n1=input()
flag=0
for i in n1:
if(i=="#"):
flag=1
break
if(flag):
break
n1=list(n1)
n2=list(input())
t1=dict()
t2=dict()
# for i in n1:
# if i not in t1:
# t1[i]=1
# else:
# t1[i]+=1
for i in n2:
&...
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