// 利用二维前缀和解决

#include<stdio.h>
#include<string.h>
#include<math.h>
#include <stdlib.h>

int main()
{
    int t = 1;
//    scanf("%d",&t);
    while(t --) {
        int n,m,k;
        scanf("%d%d%d%",&n,&m,&k);
        int a[n+1][m+1];
        for (int i = 0; i<= n; i ++) {
            for (int j = 0; j <= m; ++ j) {
                a[i][j] = 0;
            }
        }
        for (int i = 1; i<= n; i ++) {
            for (int j = 1; j <= m; ++ j) {
                scanf("%d", &a[i][j]);
                if(a[i][j] >= k) {
                    printf("1");
                    return 0;
                }
                a[i][j] += a[i-1][j] + a[i][j-1] - a[i-1][j-1];
            }
        }
        int count = 2;
        while(count <= n * m) {
            for (int i = 1; i <= n; ++i) {
                if(count % i == 0) {
                    int x = i, y = count / i;
                ...