字母统计 题解：
#include
#include
using namespace std;
int main()
{
string s;
while (getline(cin, s))
{
int cnt[26] = { 0 };
for (int i = 0; i < s.size(); i++)
{
if (s[i] >= 'A' && s[i] <= 'Z')
{
cnt[s[i] - 'A']++;
}
}
for (int i = 0; i < 26; i++)
{
cout << char('A' + i) << ":" << cnt[i] << endl;
}
}
return 0;
}
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