数字反转 题解:
#include<iostream>
using namespace std;
int a,b;
int turn(int x)
{
int sum=0;
while(x)
{
int t=x%10;
sum=sum*10+t;
x/=10;
}
return sum;
}
int main()
{
while(cin>>a>>b)
{
int num1=turn(a+b);
int num2=turn(a)+turn(b);
if(num1==num2)
cout<<a+b<<endl;
else
puts("NO");
}
return 0;
}
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