文章
36
粉丝
505
获赞
55
访问
372.5k
#include<cmath> #include<iostream> using namespace std; int main() { int m, n; cin >> m >> n; double a, b; a = m / pow(2, n); b = m * (3 - pow(0.5, n - 2)); printf("%.2f %.2f", a, b); return 0; }
The road of your choice, you have to go on !
粤ICP备16082171号-1
登录后发布评论