#include<bits/stdc++.h>
using namespace std;

int tab[2][13] = {
    {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31},
    {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31},
};

bool LeapYear(int year){
	return ( (!(year%4) && year%100) || !(year%400) );
}

int DaysOfYear(int year){
	if(LeapYear(year))
		return 366;
	else
		return 365;
}

int main(){
	int num;
	scanf("%d", &num);
	while(num--){
		int year, month, day, n;
		scanf("%d %d %d %d", &year,&month,&day,&n);
		//计算出从year开始加上天数共有多少天
		for(int i=1; i<month; i++)
			n += tab[LeapYear(year)][i];
		n += day;
		
		//刚好为一整年
		if(n==DaysOfYear(year)){
			year += 1;
			month = 1;
			day = 1;
		}
		//经过了很多个整年
		else if(n>DaysOfYear(year)){
			int t = n/DaysOfYear(year);
			year += t;
			int sum = 0;
			for(int i = year-t; i<year; i++){
				sum += DaysOfYear(i);
			}
			//定位至某一年后再进行定位具体日期
			sum = n - sum;
			for(month=1; ; month++){
				su...