s='good morning' l=len(s) index=0#用来记录s的指针 while(1): try: ss=input() index=0 l2=len(ss) count=0 ii=0#用来表示主串的指针 for i in range(l2): if(ss[i]=='g'): ii=i index=0 ...

#include <bits/stdc++.h> using namespace std; int main() { string s; while(getline(cin,s)){ int ct=0; while(s.find("good morning")!=string::npos){ s.erase(s.find("good morning"),12); ct++; } cout<<ct<<endl; } }  

#include<iostream> #include<cstdio> #include<string> #include<string.h> #include<algorithm> #include<vector> #include<map> #include<queue> using namespace std; #define ll int #define inf 0x3f3f3f3f #define MAXN 205 #define vec vector...