#include<iostream> using namespace std; double x; int n; int main() { while(cin>>x>>n) { double y=x; while(n--) y=y*2/3+x/(3*y*y); printf("%.6f\n",y); } return 0; }  

#include <bits/stdc++.h> using namespace std; int main(){ double x;int n; while(cin>>x>>n){ std::vector<double> a(n+1); a[0]=x; for(int i=1;i<=n;i++){ a[i]=a[i-1]*2.0/3.0+x/(3.0*a[i-1]*a[i-1]); } ...

#include <iostream> #include <cstdio>   using namespace std;   int main(){     // x是被求立方根的数     double x;     int iteration;     double y0;     while(cin >> x >> iteration){  ...