while(1): try: n=input() for i in n: k=ord(i) out=format(ord(i),'08b') count=out.count('1') if(count%2!=1): print("1",end='') print(out[1:]) ...

#include <stdio.h> void OddCheck(char *s) { char *p = s; while(*p != '\0') { int a[8] = {0},i = 7,n = *p,count = 0; //b获取十进制数,count记录1的个数 while(n && i >= 0) { if(n % 2 == 1) count++; a[i] = n%2; n/=2; i--; } if(count % 2 == 0) a[0] = 1; ...